2C8H18 + 25O2 → 16CO2 + 18H2O
- O₂ per mol fuel
- 12.5 mol
- Stoichiometric AFR
- 15.13 : 1
- AFR with excess air
- 15.13 : 1
- Air per kg fuel
- 11.71 m³ (0 °C)
- CO₂ per kg fuel
- 3.082 kg
- H₂O per kg fuel
- 1.419 kg
- Fuel C8H18O0: M = 114.232 g/mol
- O₂ needed = C + H/4 + S − O/2 = 8 + 18/4 + 0 − 0/2 =
12.5 mol - Air = O₂ ÷ 0.2095 = 59.67 mol × 28.965 g/mol ÷ 114.23 g/mol = AFR
15.13
Assumes complete combustion in dry air (20.95 % O₂ by volume). Nitrogen in the fuel is assumed to leave as N₂; real flames also make some NOₓ and, if air is short, carbon monoxide and soot.
How it works
For complete combustion, carbon becomes CO₂, hydrogen becomes H₂O, sulfur becomes SO₂ and fuel nitrogen is assumed to leave as N₂. The oxygen needed per mole of fuel is C + H/4 + S − O/2. Dry air is 20.95 % oxygen by volume with a molar mass of 28.965 g/mol, which gives the air needed and the mass air–fuel ratio.
The stoichiometric air–fuel ratio for petrol (modelled as octane) is about 15.1 : 1 by mass, and for natural gas (methane) about 17.2 : 1. Real burners add excess air to make sure all the fuel burns, at the cost of some heat carried away in the flue gas.
Frequently asked questions
- What is the air–fuel ratio of petrol?
- About 14.7 : 1 for real petrol blends and 15.1 : 1 for pure octane. It is the mass of air needed to burn one mass unit of fuel completely.
- How much CO₂ does burning 1 kg of methane make?
- CH₄ + 2O₂ → CO₂ + 2H₂O: 44.01 ÷ 16.04 = 2.74 kg of CO₂ per kg of methane.
- Why use excess air?
- Mixing is never perfect. A little extra air prevents unburned fuel, carbon monoxide and soot. Too much wastes energy heating air that goes up the chimney.
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