ΔT = i × K × m — fill in every field except the one you want; the empty field is solved for.
Change in boiling or freezing point (ΔT) = 1.86 °C
- Rearrange:
ΔT = i × K × m - Substitute:
(2) × (1.86 °C·kg/mol) × (0.5 mol/kg)=1.86 K
How it works
For boiling and freezing points, ΔT = i × K × m, where m is molality (mol of solute per kg of solvent) and K is the solvent's ebullioscopic (K_b) or cryoscopic (K_f) constant. The result is the size of the change: add it to the pure solvent's boiling point, or subtract it from the freezing point.
Osmotic pressure uses Π = iMRT with molarity and R = 0.082057 L·atm/(mol·K). The van 't Hoff factor i is the number of particles per formula unit: 1 for sugar, close to 2 for NaCl and 3 for CaCl₂ in dilute solution (slightly less in practice because ions pair up).
Frequently asked questions
- How much does salt lower the freezing point of water?
- For 1.00 mol of NaCl per kg of water: ΔT = 2 × 1.86 × 1.00 = 3.72 °C, so the solution freezes at about −3.7 °C.
- Why is molality used instead of molarity?
- Molality is based on mass of solvent, so it doesn't change with temperature — important when the temperature itself is what you're measuring.
- How are colligative properties used to find molar mass?
- Measure ΔT for a known mass of solute in a known mass of solvent, solve for molality, then divide the grams of solute by the moles.
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